千年加密解密代码(delphi)

快要发癫啦 · 发表于 2023-2-14 11:29:39

千年加密解密代码....虽然看起来挺复杂的.我是对应汇编的.编译后几乎和游戏客户端里的一样...保证了速度..
二次解密代码我还没去搞.不过一次解密足够了.可以制出很多功能外挂.如自动拾取.吃药.等等...二次解密加密主要用于怪物坐标用的.(自动练功需要解析怪物坐标要用)

声明部分
//二种声方法均可
//const gamestr:string[255] = ’N>TSVUJlwdcBMFjnAKb?qxvyeGzfLP=_ER@Z\am]ChgoWD;QuX[<tkpr^`iIHOYs.3" (- ’+chr(13)+’<;’+chr(12)+chr(00)+’=/!,1>#2$’+chr(39)+’89%’+chr(10)+chr(9)+’*):5&+67?40’;
const gamestr : array [0..127] of byte =
($4E, $3E, $54, $53, $56, $55, $4A, $6C, $77, $64, $63, $42, $4D, $46, $6A, $6E, $41, $4B, $62, $3F, $71, $78, $76, $79, $65, $47, $7A, $66, $4C, $50, $3D, $5F,  $45, $52, $40, $5A, $5C, $61, $6D, $5D, $43, $68, $67, $6F, $57, $44, $3B, $51, $75, $58, $5B, $3C, $74, $6B, $70, $72, $5E, $60, $69, $49, $48, $4F, $59, $73, $2E, $33, $1E, $01, $13, $22, $10, {&content}B, $28, $2D, $20, {&content}D, $19, $3C, $3B, $06, $11, $1C, {&content}C, {&content}, $3D, $1D, $2F, $21, $03, $02, $05, $04, $2C, $31, $3E, $23, $32, $24, $27, $38, $1F, $39, $25, $12, {&content}A, $09, $18, $1B, $2A, $29, $3A, {&content}E, $35, $07, $26, {&content}F, $2B, $36, $14, $37, $3F, $34, $30, $16, $08, $15, $17, $1A);

代码部分
function decode (inchar:pchar; len:integer ; outchar:pchar):integer; //解密
var
a1, d1: byte;
j, count, di, si :integer;
begin
  decode := len div 4 * 3 ;  //返回解密后数据长度
  j := 0;
  while i < len do
begin
   d1 := byte (inchar[j] );
   if ( d1 = $3B ) or (d1 = $7A) then
      begin
      end;
   d1 := d1 and {&content}FF;
   d1 := gamestr [d1 + 05];             //d1 := byte ( gamestr [ 1 + d1 ] );
   byte (inchar [j] ) := d1;       // 根据不同的gamestr数据定义选用不现的方法
   inc (i);
end;

  di := 0 ;
  si := 0 ;
  count := len div 4 ;                      //循环次数
  for j := 1 to count do
begin
   a1 := ord ( inchar [di]);             //解密数据 (取4个.转化3个)
   a1 := a1 shl 2 ;
   d1 := ord ( inchar [di + 1]);
   d1 := d1 shr 4 ;
   a1 := a1 or d1 ;
   outchar[si] := chr (a1);

   a1 := ord ( inchar [di + 1]);
   a1 := a1 shl 4 ;
   d1 := ord ( inchar [di + 2]);
   d1 := d1 shr 2 ;
   a1 := a1 or d1 ;
   outchar[si + 1] := chr (a1);

   a1 := ord ( inchar [di + 2]);
   a1 := a1 shl 6 ;
   d1 := ord ( inchar [di + 3]);
   a1 := a1 or d1 ;
   outchar[si + 2] := chr (a1);

   di := di + 4 ;
   si := si + 3 ;
  end;
end;

function encode (inchar:pchar; len:integer ; outchar:pchar):integer; //加密
var
  a1, d1 :byte;
  j,count,di,si :integer;

begin
  encode := len div 3 * 4 ;  //返回加密后数据长度
  di := 0 ;
  si := 0 ;
  count := len div 3;          //定义循环次数
  for j := 1 to count do
begin
a1 := ord ( inchar [di]); //第一次转换  取3个输出4个
a1 := a1 shr 2 ;
outchar [si] := chr (a1);

a1 := ord (inchar[di]);
a1 := a1 and 3 ;
a1 := a1 shl 4 ;
d1 := ord (inchar[di +1]);
d1 := d1 shr 4 ;
a1 := a1 or d1 ;
outchar[si +1] := chr (a1) ;

a1 := ord ( inchar[di + 1]) ;
a1 := a1 and {&content}F ;
a1 := a1 shl 2 ;
d1 := ord ( inchar[di + 2]) ;
d1 := d1 shr 6 ;
a1 := a1 or d1 ;
outchar[si + 2] := chr (a1);

a1 := ord ( inchar[di + 2]) ;
a1 := a1 and $3F;
outchar[si + 3] := chr (a1) ;

//第二次转换
d1 := ord ( outchar [si]);       //第 1 个
d1 := gamestr [d1];
outchar [si] := chr (d1);

d1 := ord ( outchar [si + 1]);       //第 2 个
d1 := gamestr [d1];
outchar [si + 1] := chr (d1);

d1 := ord ( outchar [si + 2 ]);       //第 3 个
d1 := gamestr [d1];
outchar [si + 2] := chr (d1);

d1 := ord ( outchar [si + 3]);       //第 4 个
d1 := gamestr [d1];
outchar [si + 3] := chr (d1);

di := di + 3 ;
si := si + 4 ;
end;
end;

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