千年加密解密代码....虽然看起来挺复杂的.我是对应汇编的.编译后几乎和游戏客户端里的一样...保证了速度..
+ i; q1 F7 o9 Z6 X6 s二次解密代码我还没去搞.不过一次解密足够了.可以制出很多功能外挂.如自动拾取.吃药.等等...二次解密加密主要用于怪物坐标用的.(自动练功需要解析怪物坐标要用)
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6 C7 n7 B1 i( O: i8 J5 i声明部分
( B: u3 B# N, y( w//二种声方法均可
! [6 @& V, n0 H2 c$ L1 |! a' u//const gamestr:string[255] = ’N>TSVUJlwdcBMFjnAKb?qxvyeGzfLP=_ER@Z\am]ChgoWD;QuX[<tkpr^`iIHOYs.3" (- ’+chr(13)+’<;’+chr(12)+chr(00)+’=/!,1>#2$’+chr(39)+’89%’+chr(10)+chr(9)+’*):5&+67?40’; 7 U- F' u8 q0 s
const gamestr : array [0..127] of byte =
# D3 N# p: r3 v# B F($4E, $3E, $54, $53, $56, $55, $4A, $6C, $77, $64, $63, $42, $4D, $46, $6A, $6E, $41, $4B, $62, $3F, $71, $78, $76, $79, $65, $47, $7A, $66, $4C, $50, $3D, $5F, $45, $52, $40, $5A, $5C, $61, $6D, $5D, $43, $68, $67, $6F, $57, $44, $3B, $51, $75, $58, $5B, $3C, $74, $6B, $70, $72, $5E, $60, $69, $49, $48, $4F, $59, $73, $2E, $33, $1E, $01, $13, $22, $10, {&content}B, $28, $2D, $20, {&content}D, $19, $3C, $3B, $06, $11, $1C, {&content}C, {&content}, $3D, $1D, $2F, $21, $03, $02, $05, $04, $2C, $31, $3E, $23, $32, $24, $27, $38, $1F, $39, $25, $12, {&content}A, $09, $18, $1B, $2A, $29, $3A, {&content}E, $35, $07, $26, {&content}F, $2B, $36, $14, $37, $3F, $34, $30, $16, $08, $15, $17, $1A);
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3 p& {: f( A" Y7 u5 e& A# b代码部分 ! q: t" e2 s5 y# W. `4 k
function decode (inchar:pchar; len:integer ; outchar:pchar):integer; //解密 8 z' M5 \. Z5 f- Y4 g0 \- z
var / x! {) i% b+ J( a6 G% U& B! V" B
a1, d1: byte;
) X) [, x$ I: R j, count, di, si :integer; ! Z8 a: d% |) {! P, I. R
begin # ]7 }4 k, }) N& \
decode := len div 4 * 3 ; //返回解密后数据长度 3 c0 Y6 E$ E [, m. |2 u: q+ A- L
j := 0;
2 q( G- i- m, S0 k: @" C while i < len do . A1 s3 l2 w. k
begin 2 ^+ }6 F# d' D, O" x* A
d1 := byte (inchar[j] ); $ `! S5 l; X' w6 m. I8 `+ Q
if ( d1 = $3B ) or (d1 = $7A) then
% {% w8 F5 ? A1 E9 O begin , d: m0 v) e( X- |3 B
end; 7 \4 D; Y" _1 c8 ?$ w3 L
d1 := d1 and {&content}FF; / G( l' N, T! T1 D! M' {+ O
d1 := gamestr [d1 + 05]; //d1 := byte ( gamestr [ 1 + d1 ] ); 8 v# N, w8 _" [" g* i" d
byte (inchar [j] ) := d1; // 根据不同的gamestr数据定义选用不现的方法 + g/ y0 O" F# k* S" i% `$ \& e
inc (i);
; t! Q- p' c( Q3 F, d5 P end; ! K; r# g. u& C
! t: k7 H9 B: U! [' ]2 V di := 0 ; # U9 T3 G& }! ]4 [" @# d
si := 0 ; ) d5 q) D3 q3 r- ~0 ?
count := len div 4 ; //循环次数 6 j# H. U/ E( X' Y% |+ f
for j := 1 to count do
0 Z2 U4 W# U- L) G begin 6 f4 T, r1 E- U+ G/ y" g; R5 {
a1 := ord ( inchar [di]); //解密数据 (取4个.转化3个)
3 Q5 V8 W' ^2 \- W/ V6 i V a1 := a1 shl 2 ;
+ k- u/ W# u8 w4 d* R( W# k d1 := ord ( inchar [di + 1]); & o2 T- S$ N0 Z% F# ~# D& l1 `% _
d1 := d1 shr 4 ;
4 q9 x! M* G: ~( K& n7 n a1 := a1 or d1 ;
* F+ q$ \2 ~& E outchar[si] := chr (a1);
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, j+ J, o' \$ G: n1 X7 Z2 p a1 := ord ( inchar [di + 1]);
7 L) ]: z* K s! P6 h- ` a1 := a1 shl 4 ;
/ Z! k( P% ?, l7 N d1 := ord ( inchar [di + 2]); ' A% M5 _" X. \8 s3 J
d1 := d1 shr 2 ;
( X; ~: v7 A. S( e a1 := a1 or d1 ;
, v: ~( i! G! B9 x4 m S' s outchar[si + 1] := chr (a1);
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% v8 q; E/ g8 f1 r" k4 v! M) j a1 := ord ( inchar [di + 2]);
9 A% `4 ^. N5 H. K1 o3 L a1 := a1 shl 6 ;
- a9 u% b* |4 Q* i, _ d1 := ord ( inchar [di + 3]);
( x! Z i4 e3 b9 D2 i0 u a1 := a1 or d1 ;
\1 J, K9 f2 A+ V, l% p% F2 S outchar[si + 2] := chr (a1);
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9 K. j* b, W9 M ^) t di := di + 4 ;
: }- V; G# |. P$ C) \" r si := si + 3 ;
8 P) K" |* X, x3 X, f0 t2 V end;
7 O2 \8 o" t( W+ r" l" S* K$ nend; 2 ^# C* D& m- n
4 [ c. ~% v- W X+ c7 Ofunction encode (inchar:pchar; len:integer ; outchar:pchar):integer; //加密 + v0 z8 D# _! H5 |4 `( ]8 Z8 l; N# r7 Y
var , ^7 N& Q* I8 g; B6 F. p
a1, d1 :byte; % n) ^/ h0 P% `! ^( ]* }4 a5 U
j,count,di,si :integer; . V- i# Q' c' V3 r/ \% K! n
3 U l" _7 Z$ k2 e/ nbegin , s r2 Y% N: @+ @% t% e' f7 w4 m% \
encode := len div 3 * 4 ; //返回加密后数据长度
. y7 ]5 u6 l4 W5 p3 p di := 0 ;
' p9 k6 _- p* Q" L b; `" }8 d2 b3 J si := 0 ;
& x% L" k9 G6 q! c) I( q count := len div 3; //定义循环次数 + c; i2 @! r/ r0 u# y5 k, U
for j := 1 to count do
4 G% }& t) m& N4 |5 V+ r begin # A# i8 z) W w1 K
a1 := ord ( inchar [di]); //第一次转换 取3个 输出4个 2 |. M0 `1 z. d9 {9 p5 Q
a1 := a1 shr 2 ; , i, t6 d, [( `. a+ M
outchar [si] := chr (a1);
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a1 := ord (inchar[di]);
4 k& u) v/ B+ K. u+ o a1 := a1 and 3 ; ( }; ~2 C0 G, G8 H# l$ ]2 d5 m# z I
a1 := a1 shl 4 ;
" y# \/ i% j8 k$ B% K d1 := ord (inchar[di +1]);
& B4 Q6 S! x8 j1 K1 Y+ i d1 := d1 shr 4 ;
8 I5 ]- U2 Z* V" `. F; A6 g a1 := a1 or d1 ;
, ]$ q$ H6 ^& E, q outchar[si +1] := chr (a1) ; 1 r; _3 T4 f" A+ o# y
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a1 := ord ( inchar[di + 1]) ; 5 f2 [+ ` f7 p5 C# M
a1 := a1 and {&content}F ;
7 }+ W2 m/ Q3 ] a1 := a1 shl 2 ; 3 r- b( a# K: g4 }2 P
d1 := ord ( inchar[di + 2]) ;
/ X' g! Z8 c) F! p% t9 e# | d1 := d1 shr 6 ;
3 J! y; V6 {& s3 M a1 := a1 or d1 ;
1 e) o. W& I8 C: ?* \ outchar[si + 2] := chr (a1);
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- n% X0 l( Z5 S3 @' i7 ?. a a1 := ord ( inchar[di + 2]) ;
. J& G5 ?+ o b S5 e2 i) x a1 := a1 and $3F; " g" ?0 U; q& @7 A
outchar[si + 3] := chr (a1) ;
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//第二次转换
9 f" u: I! [& W% L1 F: K$ V d1 := ord ( outchar [si]); //第 1 个 ; z1 M3 J+ m3 n2 g# c! S
d1 := gamestr [d1]; ; q% ^+ d& E6 l$ e- {& F1 V2 S9 _# E
outchar [si] := chr (d1);
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' r9 _+ J0 X2 Z% N. |% n d1 := ord ( outchar [si + 1]); //第 2 个 & N' d+ ^ Q& b6 B0 ~' H
d1 := gamestr [d1]; 6 B8 F( N8 c, u" I& s
outchar [si + 1] := chr (d1);
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d1 := ord ( outchar [si + 2 ]); //第 3 个 0 l/ L m2 D8 N! x4 L/ q! m
d1 := gamestr [d1];
% i6 T* s! G3 q outchar [si + 2] := chr (d1);
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d1 := ord ( outchar [si + 3]); //第 4 个
' B" W8 u( V$ ^7 i" K d1 := gamestr [d1];
& X9 T- h" [# b9 X8 b! H7 t" w' e outchar [si + 3] := chr (d1);
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9 t6 x" y9 @7 c- { di := di + 3 ;
7 l1 z7 I% N0 o0 C, w si := si + 4 ; % @( t2 }/ O. O" `, r7 {
end;
8 U* w# w2 d4 Q) |7 a) S3 S( Pend; 7 I6 M; u r Z3 N5 x N
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