千年加密解密代码....虽然看起来挺复杂的.我是对应汇编的.编译后几乎和游戏客户端里的一样...保证了速度.. ' } u: u" S6 a) O
二次解密代码我还没去搞.不过一次解密足够了.可以制出很多功能外挂.如自动拾取.吃药.等等...二次解密加密主要用于怪物坐标用的.(自动练功需要解析怪物坐标要用)
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声明部分 + `1 |" F3 K3 {0 a4 l5 P
//二种声方法均可 6 X$ z% [/ u& K+ I* h8 R, o Z( R. D
//const gamestr:string[255] = ’N>TSVUJlwdcBMFjnAKb?qxvyeGzfLP=_ER@Z\am]ChgoWD;QuX[<tkpr^`iIHOYs.3" (- ’+chr(13)+’<;’+chr(12)+chr(00)+’=/!,1>#2$’+chr(39)+’89%’+chr(10)+chr(9)+’*):5&+67?40’;
; X. @+ x3 l) w, t% k0 q' kconst gamestr : array [0..127] of byte = 2 |, |5 @' I0 U" m7 }7 y
($4E, $3E, $54, $53, $56, $55, $4A, $6C, $77, $64, $63, $42, $4D, $46, $6A, $6E, $41, $4B, $62, $3F, $71, $78, $76, $79, $65, $47, $7A, $66, $4C, $50, $3D, $5F, $45, $52, $40, $5A, $5C, $61, $6D, $5D, $43, $68, $67, $6F, $57, $44, $3B, $51, $75, $58, $5B, $3C, $74, $6B, $70, $72, $5E, $60, $69, $49, $48, $4F, $59, $73, $2E, $33, $1E, $01, $13, $22, $10, {&content}B, $28, $2D, $20, {&content}D, $19, $3C, $3B, $06, $11, $1C, {&content}C, {&content}, $3D, $1D, $2F, $21, $03, $02, $05, $04, $2C, $31, $3E, $23, $32, $24, $27, $38, $1F, $39, $25, $12, {&content}A, $09, $18, $1B, $2A, $29, $3A, {&content}E, $35, $07, $26, {&content}F, $2B, $36, $14, $37, $3F, $34, $30, $16, $08, $15, $17, $1A);
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- ?8 _) ?7 f9 P1 C& r代码部分
$ k6 V3 M- @- Y$ Tfunction decode (inchar:pchar; len:integer ; outchar:pchar):integer; //解密
# B# K* F: m9 i5 W- {var
, H! T$ c( G0 `4 O, P2 G a1, d1: byte; 4 U, r+ k- u, `. p7 ~6 L
j, count, di, si :integer;
/ d' U- ?3 h6 p1 U/ e3 [- @7 |( ]/ ubegin # R4 J# N$ o f8 `; x/ g* o- I
decode := len div 4 * 3 ; //返回解密后数据长度 9 D, ~8 E" L/ a! R
j := 0;
& x- a9 A, d* A& a# X. [ while i < len do ( g* N6 R: h. M- `. F6 R) A' O
begin
- p& j( S$ w6 V" k. ~8 y- { d1 := byte (inchar[j] );
' A1 T! V5 p. h if ( d1 = $3B ) or (d1 = $7A) then % W0 a" P2 e3 d
begin
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d1 := d1 and {&content}FF; + a6 q! F( H5 b/ m- J
d1 := gamestr [d1 + 05]; //d1 := byte ( gamestr [ 1 + d1 ] );
/ Z% Q+ H; n: @ byte (inchar [j] ) := d1; // 根据不同的gamestr数据定义选用不现的方法
) | [% {3 l8 r$ @. k1 ] inc (i); * Z$ C; ]7 T/ Z" C
end;
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/ R& D, F4 Y3 n _, T. [ di := 0 ;
; `( @# L% p. | si := 0 ; - H# y' ? q5 P6 Q- V
count := len div 4 ; //循环次数
9 X3 p0 l& [0 s# I for j := 1 to count do
5 Z7 M# X4 ~. a begin
c: }+ o' U2 U3 Y1 Y$ i a1 := ord ( inchar [di]); //解密数据 (取4个.转化3个)
; r' z3 ?" n* c' Q1 }5 u4 J7 } a1 := a1 shl 2 ; 8 R+ c+ |/ z0 l
d1 := ord ( inchar [di + 1]);
0 Z \( l& E& N/ P0 v0 h' Z d1 := d1 shr 4 ;
- @# A: d" p7 V5 {" E a1 := a1 or d1 ; / ?2 W" b u0 }- w
outchar[si] := chr (a1);
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4 Q8 Z7 a0 \ W5 [1 m$ l) @ a1 := ord ( inchar [di + 1]);
; a1 m5 r& h. \3 a a1 := a1 shl 4 ; 9 S# v, H) z& H, p3 {( G
d1 := ord ( inchar [di + 2]);
: v" }" J5 I; \ d1 := d1 shr 2 ; & j8 X# a4 S* }8 u+ I
a1 := a1 or d1 ; ) W1 T( _' W0 Y$ a$ }$ l5 R
outchar[si + 1] := chr (a1);
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a1 := ord ( inchar [di + 2]);
: h, w& G/ ? K6 }4 H1 f a1 := a1 shl 6 ;
4 q, N, j2 E" t$ E5 k( G d1 := ord ( inchar [di + 3]); " r G2 [3 N1 d% _3 n+ G$ A8 D/ B
a1 := a1 or d1 ;
' |% G1 p9 j2 @6 w' w: ]2 j outchar[si + 2] := chr (a1); 2 C: q! C: P. S r6 q9 M
5 s3 |& \7 A% n. o9 l' ?; v- U di := di + 4 ;
8 [! [. ~) U7 d# n7 f si := si + 3 ; Q5 }9 h1 Z; t8 ^
end;
4 i7 i% ]3 f K% |7 P0 ~7 {end; & N" Z/ X% U; k. S
4 U ^" t$ X7 Z: u6 v* Wfunction encode (inchar:pchar; len:integer ; outchar:pchar):integer; //加密 ( }6 h. k p6 l! H4 Z) U; w
var W4 o) y7 I8 Q2 |
a1, d1 :byte; * |! C4 n. Q' W/ I/ V
j,count,di,si :integer;
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% }2 ]- | y2 O9 |0 I& _3 o1 xbegin 9 K; W" E4 ~ v0 ~
encode := len div 3 * 4 ; //返回加密后数据长度
2 ^3 [+ W! x2 ~! F' e di := 0 ; $ S* S' |& p) H0 n( C0 Q
si := 0 ; . Z. w3 H9 k3 r7 i, k
count := len div 3; //定义循环次数 4 y: O, I0 t0 b! j8 ]' u
for j := 1 to count do 5 ~. u4 i1 x$ B
begin : O+ F( Y. ]- A7 B- G
a1 := ord ( inchar [di]); //第一次转换 取3个 输出4个
# m# Z: m9 h8 I- N a1 := a1 shr 2 ; # H7 {0 N' ^$ H; |
outchar [si] := chr (a1); 6 R) s. r+ T% N6 R. H
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a1 := ord (inchar[di]); 3 f. [$ y: U7 r8 o, D/ n8 ]
a1 := a1 and 3 ; ; A( M. A# k4 g, i/ j. o
a1 := a1 shl 4 ; * I' X8 g- i) K f+ ^" b: D$ Q& ^* c! @
d1 := ord (inchar[di +1]); $ _% p: _- `$ P' d
d1 := d1 shr 4 ;
z3 ~% L( A/ D L4 b a1 := a1 or d1 ; 5 z* L/ ~+ I f. |( \9 v* n" y& v
outchar[si +1] := chr (a1) ; + r& L+ P7 c, ^) y
S( j+ ~* y8 F. M8 ?: r a1 := ord ( inchar[di + 1]) ;
$ p3 Z |4 x" _2 |( U a1 := a1 and {&content}F ;
3 y6 ]* F3 n! s! Q" ~2 Y a1 := a1 shl 2 ; 4 N: L. f- W4 B6 N f
d1 := ord ( inchar[di + 2]) ;
: Z& C1 N# f7 o& F) H d1 := d1 shr 6 ;
& p- g' [+ J/ d0 z4 S! s a1 := a1 or d1 ; . X/ D5 |+ \+ Y3 `7 r& s g( q
outchar[si + 2] := chr (a1);
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a1 := ord ( inchar[di + 2]) ; % J3 O) C- r1 S# D
a1 := a1 and $3F;
( X. [, Z8 r! B/ O% a outchar[si + 3] := chr (a1) ;
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9 g) ?2 T. x" W6 f: \* A& X& X //第二次转换
7 n# ?+ ^$ h5 w3 [' Y4 Z4 Y d1 := ord ( outchar [si]); //第 1 个 8 a* C+ e& o) Q2 |( s0 y, x
d1 := gamestr [d1]; ! X& n" @: K, a) r+ T
outchar [si] := chr (d1); & H8 `& ]. T; v* f# Z2 O5 q7 \) Q
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d1 := ord ( outchar [si + 1]); //第 2 个
6 u* ~$ a6 U9 O7 u d1 := gamestr [d1]; - ^- D, X- y9 B
outchar [si + 1] := chr (d1); $ P: B' C7 N! K* H: E9 Q/ j
6 a% S$ o/ E! R d1 := ord ( outchar [si + 2 ]); //第 3 个 . G j5 y9 v0 j1 s* B
d1 := gamestr [d1];
2 L% i4 X) q2 K* C: i# G: g outchar [si + 2] := chr (d1); / _# Z, N- }# u0 U3 y2 j" W
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d1 := ord ( outchar [si + 3]); //第 4 个 $ y5 K6 e- C5 I5 f" E0 l9 ~% c) `
d1 := gamestr [d1]; 9 C7 a t3 Z4 D7 R5 _2 C5 E d
outchar [si + 3] := chr (d1); 4 ?$ {) H n1 b+ ^. D0 B
0 p' g% A2 U+ y4 P, Q di := di + 3 ; 4 G5 N7 i, ?0 | W- S2 K
si := si + 4 ; # V/ ?% n9 i9 d9 n m* n
end; ' ~2 M0 E1 Q7 ]9 V6 Y
end; * ^& I: D+ B* q
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